PHCC
Too fast for you to see me.
Feynman Ciphers said:
I saw this sometime ago, and it really made my brain explode. How can someone create a so difficult code? Is it worth to try solving it?
Seriously, those secret messages makes everyone curious to see what words are hidden in the code. Well, I just wanted to give it a try, and I already saw some important things from the two last unsolved codes :
The 2nd and 3rd ciphers have some codes in common, and some codes that repeats only in themselves:
XUKEXWSLZJUAXUNKIGWFSOZRA(1)WURO(2)RKXAOS
LHR(3)OBXBTKCMUWDVPTFBLMKEFVWMUXTVT(4)WUI
DDJVZKBRMCWOIWYDXML(5)UFPVSHAGSVWUFWOR
C(4)WUIDUJCNVTTBERTUN(6)OJUZHVTWKORSVRZSV
VFSQXOCMUWPYTRLGBMCYPOJCLRIYTVFCCMU
W(5)UFPOXCNMCIWMSKPXEDLYIQKDJWIWCJUMVR
CJUMV(2)RKX(1)WURKPSEEIWZVXULEIOETOOFWKBI
UXPXUGOWLFPWUSCH
(1)WURVFXGJYTHEIZXSQXOBGSVRUDOOJXATBKT
ARVIXPYTMYABMVUFXPXKUJVPLSDVTGNGOSI
GLWURPKFCVGELLRNNGLPYTFVTPXAJOSCWRO
DORWNWSICLFKEMOTGJYCRRAOJVNTODVMNSQ
IVICRBICRUDCSKXYPDMDR(6)OJUZICRVFWXIFP
XIVVIEPYTDOIAVRBOOXWRAKPSZXTZKVROSW
CRCFVEESOLWKT(3)OBXAUXVB
I didn't mark all of them because I'm lazy, but I'll put them right here:
Repeated codes ~
WUID
CJUMVR (twice consecutively in message 2)
OJUZ
CMUW
WUR
SQXO
ICR
PYT
RKX
OBX
VTW
UFP
GSV
WUF
SVR
KPS
XPX
RVF
GJY
RUD
This means that the two messages must use the same logic to solve them.
Well, that's what I have for now. So, who likes logic games and wants to solve this once for all?
Question: Is this topic even going to be open?
EDIT:
Well, let's make some progress here. If I consider the 3 letter+ codes as entire words, maybe I can find some encoded conjuctions, or 1-3 letter words, such as "for", "and", "nor", "but", "or", "yet", "so", "to", etc. Let's try it:
Some encoded words separated by other encoded words :
CJUMVR KX WUR - were KX is a 2-letters word. It can be - "to", "or", "so", "if", "in", "by", "as", "an", "is" or "it".
WUR O RKX - It must be "a" or "I". Or, if I consider "KX" as a separated word, we have "OR", that can be a 2-letters word.
WUF WORC WUID - It seems that we have a 4-letters word here. Well, let's put this aside for now.
OJUZ H VTW - Again , it must be "a" or "I".
ICR B ICR - "a" or "I".
SQXO B GSV - Again, B. It has now even more chances of being "a" or "I".
OBX BTK CMUW - If we just consider that this is a conjunction, we can have: "for", "and", "nor", "but" or "yet". If it isn't a conjunction, there will be too much possibilities to try. So, let's put this aside too.
Ok, these are the ones that I've found. Let's start with KX. If KX starts with "i", in the alphabet, "K" is two cases after "I". We have some options here : K(2) X(3) - Where K is two cases after the real letter, and X is three cases after the real letter, which will give us "iu". Or K(2)X(4), where X is four cases after the real letter, which will give us "it". Maybe the text is encoded entirely in one of these this ways? Let's see if it works with the begin of the 2nd text:
X(2) U(4) K(6 or 8) E(8 or 16) - V Q (E or C) (W or O) - V Q E W - V Q C W - V Q E O - V Q C O. None of these words exists.
X(2) U(3) K(4) E(5) - V R G A - This word doesn't exist.
Well, let's try other sequences:
W(1) U(2) R(3) - XWU
W(3) U(2) R(1) - ZWS
W(-1) U(-2) R(-3) - VSN
W(-1) U(-1) R(-1) - VTQ
W(-3) U(-2) R(-1) - TSQ - I think that I've found something here. Are only the initial letters being encoded by this way? If the initial letter is set by the length of the word, chances are that WUR represents "THE". So, what's the connection between H-U and E-R? In the alphabet, H is 13 cases far from U. The thing become interesting when E is equally 13 cases far from R, just like in H-U. But I don't see why 10 were added in the word's length. Maybe I could try to discover this later.
Well, setting the initial letters by the word's length, we have KX with the initial letter being I. So, it can be IF, IT, IN or IS.
We saw that B can be A or I. If we follow this rule, B will represent A. But we saw too that H can be A or I. In this case, it was +1, not -1. Maybe H makes composition with another word? I don't know.
If we take the code "SQXO B GSV", it will result in "O***/ A / D**". In D**, there must be a vowel in the middle. The problem is seeing how S is connected with a vowel.
Maybe I should try to get some more progress before coming back again, that's it for now.
EDIT2:
I found this site : http://www.aerobushentertainment.com/crypto/index.php?topic=47.0;prev_next=prev#new
I saw that this guy tried by the same method as me (well, actually he have done much more than I), but it seems that he stopped trying it. His method is very interesting.
It was found the sequence for the 2, 3 and 4 letter words:
2 letter : -2 -3
3 letter : -3, -20, -6
4 letter : -4, -5, -20, -10
Let's decode some words :
WUR = TAL (http://wold.livingsources.org/word/72142315364909779)
PYT = MEN
ICR = FIL
SQXO = OLDE
VR = TO
CMUW = YHAM
OJUZ = KEAP
WUID = SPOT
JWIW = FROM
B = A
GSV = DYP (http://en.wiktionary.org/wiki/dyp)
Well, the problem is that not all the codes fits in this sequence. There must be another way solve this.
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